Statement 1: The order of reactivity of carbonium ions is $1^0>2^0>3^0$

Statement 2: Carbon atom in carbonium ions is in ${\mathrm{sp}}^3$ state of hybridization.

The order of reactivity of carbonium ions is $1^0>2^0>3^0$.  Carbon atom in carbonium ion is in ${\mathrm{sp}}^2$ state of hybridization. The three hybridized orbitals lie in the same plane and are involved in the formation of three $\sigma$ bonds with three atoms or groups while the unhybridized p-orbital remains vacant.