Statement-1: The $5^{\mathrm{th}}$ period of periodic table contains 18 elements not 32.

Statement-2: n = 5, l = 0, 1, 2, 3. The order in which the energy of available orbitals 4d, 5s and 5p increases is 5s < 4d < 5p and the total number of orbitals available are 9 and thus 18 electrons can b accommodated.

18 elements, not 32, make up the fifth period of the periodic table.

$\mathrm{n}=5,$

$\mathrm{l}=0\text{ to }(\mathrm{n}-1),$

$\mathrm{l}=0-4;0,1,2,3,4$

The beginning orbital for the fifth period is 4 s. Consequently, 2 electrons fill up 4s. 4p is multiplied by six electrons, and 4d by ten. Therefore, a total of 18 electrons or elements may exist.