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Statement-1: When ${HCO}_{3}^{-}$ and ${CO}_{3}^{2 -}$ ions are present together, ${CaCl}_{2}$ is to be used in excess to distinguished both.
Statement-2: Excess amount of ${CaCl}_{2}$ forms soluble complex with ${HCO}_{3}^{-}$ of the formula ${[Ca {({HCO}_{3})}_{6}]}^{4}$ .

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Both (A) and (R) are true but (R) is not the correct explanation of (A)

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are false

(A) is true but (R) is false

answer is C.

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Detailed Solution

Since Ca dominates the soil adsorption complex, ${CaCl}_{2}$ solutions are more effective at removing other adsorbed cations than solutions containing other cations.

Hence, option C is correct.

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