Statement 1: ${\mathrm{BrF}}_5\text{ and }{\mathrm{SF}}_6$ both have same hybridization.
Statement 2: ${\mathrm{BrF}}_5$ is square pyramidal, while ${\mathrm{SF}}_6$ molecule is octahedral.

 The difference in the shapes of ${\mathrm{BrF}}_5$ and ${\mathrm{SF}}_6$ can be explained on the basis of VSEPR theory.

SF₆(SP³d² hybridization) —  6 bond pairs  —  Octahedral geometry.

BrF₅ (SP³d² hybridization) — 5 bond pairs and 1 lone pair — square pyramidal.