Statement-1: ${\mathrm{Cr}}^{2+}$ is a stronger reducing agent than ${\mathrm{Fe}}^{2+}$.

Statement-2: In aqueous medium, $d^3$ is more stable than $d^5$ configuration.

The ${\mathrm{d}}^3$ configuration of the ${\mathrm{Cr}}^{3+}$ ion $\left({\mathrm{t}}_{2\mathrm{g}}^3{\mathrm{e}}_{\mathrm{g}}^0\right)$ makes ${\mathrm{Cr}}^{3+}$ stable by supplying crystal field stabilisation energy. As a result, ${\mathrm{Cr}}^{2+}$ ion can readily oxidised into ${\mathrm{Cr}}^{3+}$ and function as a powerful reducing agent.

${\mathrm{Cr}}^{2+}\to {\mathrm{Cr}}^{3+}+{\mathrm{e}}^{-}$
Compared to the outer orbital (high spin) complex, the inner orbital (low spin) complex is more stable. Therefore, in an aqueous medium, the ${\mathrm{d}}^3$ form is more stable than the ${\mathrm{d}}^5$ configuration.