Statement 1: $\left[\mathrm{Fe}{\left({\mathrm{H}}_2\mathrm{O}\right)}_5\mathrm{NO}\right]{\mathrm{SO}}_4$ is paramagnetic.

Statement 2: The Fe in $\left[\mathrm{Fe}{\left({\mathrm{H}}_2\mathrm{O}\right)}_5\mathrm{NO}\right]{\mathrm{SO}}_4$ has three unpaired electrons.

Iron in $\left[\mathrm{Fe}{\left({\mathrm{H}}_2\mathrm{O}\right)}_5\mathrm{NO}\right]{\mathrm{SO}}_4$ exists in +2 oxidation state having electronic configuration (3d)⁶. The unpaired electron of NO is shifted to Fe²⁺ changing it to Fe⁺ and also changes NO to NO⁺. The electronic configuration of iron in the complex thus becomes (3d)⁷ with three unpaired electrons as in the complex, sp³d²-hybridization exists.