Statement 1: ${\mathrm{KMnO}}_4$ is purple in color due to charge transfer.

Statement 2: In ${\mathrm{MnO}}_4^{-},$ there is no electron present in d-orbital of manganese.

${\mathrm{KMnO}}_{4 }$has a purple color due to the charge transfer from the ligand $\left({\mathrm{O}}^{2-}\right)$

to the metal center. It is known as the ligand to metal transfer of charge. In ${\mathrm{MnO}}^{4-}$ , there is no electron in d orbital but it is colored ion.

Here, statement-1 is True, Statement-2 is true, and Statement-2 is NOT a correct explanation for Statement-1.