Statement-1: ${NaBO}_{3} / {OH}^{-}$ can be used for oxidation of ${Cr}^{3 +}$ to ${Cr}^{6 +}$ .
Statement-2: In alkaline medium ${NaBO}_{3}$ produces $H_{2} O_{2}$ .

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Statement-1 is False, Statement-2 is True.

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.

Statement-1 is True, Statement-2 is False.

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

answer is A.

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Detailed Solution

${Cr}^{3 +}$ may be oxidised to ${Cr}^{6 +}$ using ${NaBO}_{3} / {OH}^{-}$ .Because ${NaBO}_{3}$ formed $H_{2} O_{2}$ in an alkaline medium.

Hence Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1

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