Statement-1: ${PH}_{3}$ and ${BF}_{3}$ both are electron deficient molecule.
Statement-2: All $P - H$ bond length are identical in ${PH}_{3}$ and all $B - F$ bond length are also identical in BF3 .

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

Statement-1 is True, Statement-2 is False.

Statement-1 is False, Statement-2 is True.

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Boron in ${BF}_{3}$ has an unfilled orbital and is electron-poor. The ${PH}_{3}$ is an electron-rich compound, nevertheless. It is not an electron-deficient molecule as a result.
All P–H bond lengths are the same in ${PH}_{3}$ , and all B–F bond lengths are the same in ${BF}_{3}$ .

Watch 3-min video & get full concept clarity