Statement-1: ${PH}_{3}$ and ${BF}_{3}$ both are electron deficient molecule.
Statement-2: All $P - H$ bond length are identical in ${PH}_{3}$ and all $B - F$ bond length are also identical in BF3 .

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

Statement-1 is True, Statement-2 is False.

Statement-1 is False, Statement-2 is True.

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Boron in ${BF}_{3}$ has an unfilled orbital and is electron-poor. The ${PH}_{3}$ is an electron-rich compound, nevertheless. It is not an electron-deficient molecule as a result.
All P–H bond lengths are the same in ${PH}_{3}$ , and all B–F bond lengths are the same in ${BF}_{3}$ .

Watch 3-min video & get full concept clarity