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Statement-1: ${SO}_{2}, {NO}_{3}^{-}$ and ${CO}_{3}^{2 -}$ are isoelectronic as well as isostructural species.
Statement-2: The d and /-orbitals do not shield the nuclear charge very effectively. Therefore, there is significant reduction in the size of the ions, just after d or f orbitals have been completely filled.

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Statement-1 is False, Statement-2 is True

Statement-1 is True, Statement-2 is True, Statement-2 Is NOT a correct explanation for Statement-1.

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1

Statement-1 is True, Statement-2 is False.

answer is D.

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Detailed Solution

The compound has the following number of electrons:

$\begin{aligned} {NO}_{3}^{-} = 32 e^{-} \\ {CO}_{3}^{2 -} = 32 e^{-} \\ {ClO}_{3}^{-} = 42 e^{-} \\ {SO}_{3}^{-} = 41 e^{-} \end{aligned}$

As a result, ${NO}_{3}^{-}$ and ${CO}_{3}^{2 -}$ are isoelectronic.
The structures of ${NO}_{3}^{-}$ and ${CO}_{3}^{2 -}$ are both trigonal planar. As a result, ${NO}_{3}^{-}$ and ${CO}_{3}^{2 -}$ are likewise isostructural.

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