Statement (A) : If the interior angle of a $n$ sided regular polygon is $160°$, then the number of sides are greater than the number of diagonals of the polygon.

Statement (B) : In a regular hexagon, the exterior angle is half of the interior angle.

I)Interior angle of ‘n’ sided regular polygon $=\frac{(n-2)\times 180°}{n}$

$\frac{(n-2)\times 180°}{n}$ $=160°$           ($n$ is number of sides of a polygon)

$(n-2)\times 180°=160°\times n$

$180n-360=160n$

$180n-160n=360$

$20n=360$

$n=18$

Number of sides of polygon =18.

Number of diagonals of 18 sided polygon $=\frac{n(n-3)}{2}$

$=\frac{18(18-3)}{2}$

$=\frac{18\left(15\right)}{2}$

$=9\times 15$

$=135$

II)Interior angle of regular hexagon = 120°

Exterior angle of regular hexagon = 60°