Statement (A) : The roots of the equation  $6x^2-x-1=0$ are $\frac{-1}{2},\frac{1}{3}$.

Statement (B) : $\frac{1}{2},\frac{-3}{2}$are the roots of the equation  $4x^2-8x+3=0$.

Statement (A) : $6x^2-x-1=0$

$6x^2-3x+2x-1=0$

$3x(2x-1)+1(2x-1)=0$

$(2x-1)(3x+1)=0$

$x=\frac{1}{2},\frac{-1}{3}$

Statement (B) : $4x^2-8x+3=0$

$4x^2-6x-2x+3=0$

$2x(2x-3)-1(2x-3)=0$

$(2x-3)(2x-1)=0$

$x=\frac{3}{2},\frac{1}{2}$