Statement (A) : Ampere’s law states that the line integral of $\overrightarrow{\mathrm{B}}\cdot \overrightarrow{\mathrm{dl}}$ along a closed path round the current carrying conductor is equal to µ₀i  (i is the net current through the surface bounded by the closed path)
Statement (B) : Ampere’s law can be derived from Biot-savart’s law.

Ampere’s law states that the line integral of $\overrightarrow{\mathrm{B}}\cdot \overrightarrow{\mathrm{dl}}$ along a closed path round the current carrying conductor is equal to µ₀i  (i is the net current through the surface bounded by the closed path)

Over an arbitrary closed path,

$\oint \overrightarrow{\mathrm{B}}\cdot \mathrm{d}\overrightarrow{\mathrm{l}}={\mathrm{\mu }}_0{\mathrm{I}}_{\mathrm{in}}$

Ampere’s circuital law can be derived from Biot-savart’s law.

For a long straight current carrying conductor (applying Biot-Savart law),

$\mathrm{B}=\frac{{\mathrm{\mu }}_{\mathrm{o}}\mathrm{I}}{2\mathrm{\pi r}}$

$\mathrm{\varphi }=\oint \overrightarrow{\mathrm{B}}·\overrightarrow{\mathrm{dl}}=\oint \frac{{\mathrm{\mu }}_0\mathrm{I}}{2\mathrm{\pi r}}\mathrm{dl}$

$=\frac{{\mathrm{\mu }}_0\mathrm{I}}{2\mathrm{\pi r}}\oint \mathrm{dl}=\frac{{\mathrm{\mu }}_0\mathrm{I}}{2\mathrm{\pi r}}\times 2\mathrm{\pi r}={\mathrm{\mu }}_0\mathrm{I}$

both are true.