Statement (A): Equivalent weight of Iron in Ferrous compounds is 28

 Statement (B): Equivalent weight of Iron in Ferric compounds is 18.66.

Statement (C): One mole of sodium ions ( ${\text{Na}}^{+}$ ) containing ${\text{6.023×10}}^{23}$   ions.

In statement I : Equivalent weight of Iron in Ferrous compound ( ${\text{Fe}}^{2+}$ ),

   $\frac{56}{2}=28$                          

In statement II: Equivalent weight of Iron in Ferric compound, ${\text{Fe}}^{3+}$ , $\frac{56}{3}=18.66$

  In statement III: One mole ${\text{Na}}^{+}$ has  $6.023\times {10}^{23}$  ions.