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Statement A: Half-life of a certain radioactive element is 100 days. After 200 days, fraction left undecayed will be 25%.
Statement B: $\frac{C_{t}}{C_{0}} = {(\frac{1}{2})}^{n}$ , where symbols have standard meaning.

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Both Statement A and Statement B are true

Both Statement A and Statement B are false

Statement A is true but Statement B is false.

Statement A is false but Statement B is true.

answer is A.

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Detailed Solution

Number of half-lives $= n = \frac{t}{T} = \frac{200}{100} = 2$

$\begin{array}{l} \frac{N}{N_{0}} = {[\frac{1}{2}]}^{n} \\ = {[\frac{1}{2}]}^{2} = \frac{1}{4} = \frac{1}{4} \times 100 % \end{array}$

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