Statement (A): Hybridization in   ${\text{NH}}_{3}iss{p}^3$.

Statement (B): Hybridization in   ${\text{XeO}}_2{\text{F}}_{4}iss{p}^3{d}^2$ .

Statement (C): Hybridization in ${\text{IF}}_{7}iss{p}^3{d}^3$ .

In ${\text{NH}}_3$ , the central atom is nitrogen (N).  The electron configuration of nitrogen is ${\text{1s}}^{\text{2}}{\text{2s}}^{\text{2}}2{\text{p}}_{\text{x}}^{\text{1}}2{\text{p}}_{\text{y}}^{\text{1}}2{\text{p}}_{\text{z}}^{\text{1}}$ . The intermixing of one 2s orbital and three 2p orbitals of nitrogen atom to produce four new ${\text{sp}}^{\text{3}}$  hybridized orbitals of equivalent energy.                          

                                         

In ${\text{XeO}}_2{\text{F}}_4$ , the central atom is Xenon (Xe).  The valency electronic configuration of  Xenon is ${\text{5s}}^{\text{2}}{\text{5p}}^{\text{6}}$ .  The valency electronic configuration of  Xenon in fourth excited state is ${\text{5s}}^{\text{1}}{\text{5p}}^{\text{3}}{\text{5d}}^{\text{4}}$ . The intermixing of one 5s orbital, three 5p orbitals, two 5d orbitals to produce six  new ${\text{sp}}^{\text{3}}{\text{d}}^{\text{2}}$  hybridized orbitals of equivalent energy. 

Finally the structure of ${\text{XeO}}_2{\text{F}}_4$ is as shown below:

                                    

In ${\text{IF}}_7$ the central atom is iodine (I).  The valency electronic configuration of  iodine is ${\text{5s}}^{\text{2}}{\text{5p}}^5$ .  In third excited state, the valency electronic configuration iodine is ${\text{5s}}^{\text{1}}{\text{5p}}^{\text{3}}{\text{5d}}^3$ .  The intermixing of one 5s orbital, three 5p orbitals, three 5d orbitals to produce  sevem new ${\text{sp}}^{\text{3}}{\text{d}}^3$  hybridized orbitals of equivalent energy.

Finally the structure of ${\text{IF}}_7$ is as shown below: