Statement (A): Number of anti bonding electrons in ${\mathrm{H}}_2$ is zero. 

Statement (B): Bond order of ${\mathrm{Li}}_2$molecule is 1.

Statement (C): Total number of electrons present in ${\mathrm{Ne}}_2$ molecule is 20.

The molecular orbital electronic configuration of ${\mathrm{H}}_2$ molecule is $\mathrm{\sigma }1{\mathrm{s}}^2.$

The total number of bonding electrons in ${\mathrm{H}}_2 \mathrm{is} \mathrm{two}$

The total number of anti bonding electrons in ${\mathrm{H}}_2$ is zero because there are no electrons in anti bonding $\left({\mathrm{\sigma }}^{*}\right)$ molecular orbitals.

The molecular orbital electronic configuration of ${\mathrm{Li}}_2$ molecule is $\mathrm{\sigma }1{\mathrm{s}}^2,{\mathrm{\sigma }}^{*}1{\mathrm{s}}^2,\mathrm{\sigma }2{\mathrm{s}}^2$

Bond order of ${\mathrm{Li}}_2 \mathrm{molecules}=\frac{1}{2}({\mathrm{N}}_{\mathrm{b}}-{\mathrm{N}}_{\mathrm{a}})$

$=\frac{4-2}{2}=\frac{2}{2}=1$

The molecular orbital electronic configuration ${\mathrm{Ne}}_2$ molecule is

So, total number of electrons present in ${\mathrm{Ne}}_2$ molecule is 20.