Statement (A): One equivalent of chlorine  = 35.5g

 Statement (B): Two equivalents of chlorine  = 7.10g

  Statement (C): Three equivalents of chlorine = 106.5g

We know that “number of equivalents is equal to the ratio of weight of the compound or ion to equivalent weight.

  $\text{No . of equivalents = }\frac{\text{Weight\hspace{0.17em}of compound}}{\text{Equivalent\hspace{0.17em}weight of compound}}$

 Case 1: Consider one equivalent of chlorine.

  $\text{1\hspace{0.17em}= }\frac{\text{Weight\hspace{0.17em}of chlorine}}{\left(\frac{71\text{\hspace{0.17em}g}}{2}\right)}$  ; Since molar mass of chlorine  = 71.0g

Now,  $\text{Weight of chlorine = 1}\times \text{35\hspace{0.17em}g\hspace{0.17em}= 35\hspace{0.17em}g}$

Case 2: Consider two equivalents of chlorine.

$\text{2= }\frac{\text{Weight\hspace{0.17em}of chlorine}}{\left(\frac{71\text{\hspace{0.17em}g}}{2}\right)}$

 And then, $\text{Weight of chlorine = 2}\times \text{35\hspace{0.17em}g\hspace{0.17em}= 71.0g}$ 

Case3: Consider three equivalents of chlorine.          

$\text{3\hspace{0.17em}= }\frac{\text{Weight\hspace{0.17em}of chlorine}}{\left(\frac{71\text{\hspace{0.17em}g}}{2}\right)}$

 From the above equation, $\text{Weight of chlorine = 3}\times \text{35\hspace{0.17em}g\hspace{0.17em}= 106.5g}$