Statement A : The Expression for the frequency of radiation emitted when a hydrogen atom de-excites from level ‘n’ to level (n-1) is equal to the classical frequency of revolution of the electron in the orbit, for large values of n.
Statement B : The Bohr’s Formula for the H-atom remains unchanged if proton had a charge (+4e/3) and electron a charge (–3e/4) where e = 1.6 × 10^–19C

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Both ‘A’ and ‘B’ are correct

‘A’ is correct & ‘B’ is wrong

Both ‘A’ and ‘B’ are wrong

‘A’ is wrong & ‘B’ is correct

answer is A.

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Detailed Solution

$v = \frac{m e^{4}}{(4 π)^{3} ε_{0}^{2} (h / 2 π)^{3}} [\frac{1}{(n - 1)^{2}} - \frac{1}{n^{2}}] = \frac{m e^{4} (2 n - 1)}{(4 π)^{2} ε_{0}^{2} (h / 2 π)^{3} n^{2} (n - 1)^{2}}$

For large values of n,

$\begin{aligned} 2 n - 1 ~ 2 n \\ n - 1 ~ n \end{aligned}$

$v ≅ \frac{{me}^{4}}{32 π^{3} ε_{0}^{2} (h / 2 π)^{3} n^{3}}$

The Bohr’s Formula for the H-atom remains unchanged if proton had a charge (+4e/3) and electron a charge (–3e/4) where e = 1.6 × 10^–19C because in Coulomb's Law the product of charges remains same i.e., $- e^{2}$ .

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