Q.

Statement (A): The hybridization in  XeOF2 is  sp3d .

Statement (B): The hybridization in   BrF5 is sp3d2  .

Statement (C): The hybridization in XeO2F4  is  sp3d2 .

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a

All the above statements are incorrect            

b

A and B are correct but C is incorrect

c

All the above statements are correct

d

A and B are incorrect but C is correct

answer is A.

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Detailed Solution

XeOF2 : sp3d - central atom is Xe.  In Xe excited five orbitals are available one s, three p and one d orbitals hybridized and form new five sp3d hybride orbitals.

BrF5 : sp3d2  - central atom is Br.  In 2nd excited state available six orbitals.  One s, three p and two d orbitals hybrized and form six new sp3d2 hybride orbitals.

XeO2F4 : sp3d2  - central atom is Xe. In 2nd excited state available six orbitals.  One s, three p and two d orbitals hybrized and form six new sp3d2 hybride orbitals.

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Statement (A): The hybridization in  XeOF2 is  sp3d .Statement (B): The hybridization in   BrF5 is sp3d2  .Statement (C): The hybridization in XeO2F4  is  sp3d2 .