Statement A: The time period of a simple pendulum of infinite length is infinite.
Statement B: The time period of a simple pendulum is directly proportional to the square root of length.

If length of the pendulum is large, g no longer remains vertical but will be directed towards the centre of the earth and expression of the time period is given by
T = $2\mathrm{\pi }\sqrt{\frac{1}{\mathrm{g}({\displaystyle \frac{1}{\mathrm{l}}}+{\displaystyle \frac{1}{\mathrm{R}}})}}$

Here, R is the radius of earth.
$\mathrm{if} \mathrm{l} \underset{ }{\to } \infty$, $\frac{1}{\mathrm{l}}\to 0$

and $T = 2\mathrm{\pi }\sqrt{\frac{\mathrm{R}}{\mathrm{g}}} = 84.6 \min$

In general, time period of a simple pendulum
 

$T = 2\mathrm{\pi }\sqrt{\frac{\mathrm{l}}{\mathrm{g}}}$

or $\mathrm{T} \propto \sqrt{\mathrm{l}}$