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Q.

Statement (A): xaxbcxbxcaxcxab=1

Statement (B): (x+y)(x1+y1)1=xy

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a

Both A and B are true

b

Both A and B are false

c

A is true and B is false

d

A is false and B is true

answer is A.

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Detailed Solution

A:  (xaxb)c(xbxc)a(xcxa)b

=(xab)c.(xbc)a.(xca)b

=x(ab)c.x(bc)a.x(ca)b

=xacbc.xbaca.xcbab

xacbc+abac+bcab=x0=1

B: (x+y)(x1+y1)1

=(x+y)(1x+1y)1

=(x+y)(xy(x+y))=xy

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