Statement –I:- If the Brewster’s angle for the light, propagating from air to glass is $\theta ,$ then Brewster’s angle for the light propagating from glass to air is $\frac{\pi }{2}-\theta .$

Statement –II:- The Brewster’s angle for the light propagating from glass to air is ${\tan }^{-1}\left({\mu }_g\right).$ Where ${\mu }_g$ is the refractive $indexofglass.$

In the light of above statements, choose the correct answer from the options given below;