Statement I : Be forms [BeF₄]^2- but Al forms [AlF₆]^3-
Statement II : Be does not have d-orbitals in the valence shell but Al has

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Both statement I and statement II are false

Statement I and II are correct

Statement I is incorrect and II correct

Statement - I is correct and statement - II is incorrect

answer is A.

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Detailed Solution

"Be" Maximum covalency is 4. Since in its valency shell [n=2] it has 3-orbitals only, those are one 2s & three 2p orbitals

Where as in case of "Al" due the presence of empty 3d-orbitals in its valency shell, it can extends its valency upto "6"
Ex :- "Al" forms [AlF₆]^-3

$∴$ Statement - I and Statement - II are correct

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