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Statement I: Bond order of helium is always zero.
Statement II : The number of electrons in bonding molecular orbital and antibonding molecular orbital is equal.

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Statement I and Statement II are true.

Statement I is false and Statement II is true.

Statement I is true and statement II is false.

Statement I and Statement II are false.

answer is A.

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Detailed Solution

${He}_{2} - {(σ_{1 s})}^{2} {(σ_{1 s}^{*})}^{2}$

$Bond order = \frac{Number of electrons in BMO - Number of electrons in ABMO}{2}$

$= \frac{2 - 2}{2} = o$

$∴$ I & II are ture.

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