Statement I : Boric acid burnt with ethyl alcohol in green edged flame.
Statement II : Boric acid when burnt with ethyl alcohol it forms tri ethyl orthoborate.

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Statement I is true Statement II is false

Both Statements are true

Statement I is false and Statement II is true

Both Statements are false

answer is A.

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Detailed Solution

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$\mathop {B{{(OH)}_3}}\limits_{Ortho\,boric\,\,acid} + \mathop {3{C_2}{H_5}OH}\limits_{Ethyl\,\,alcohol} \xrightarrow{{Conc.{H_2}S{O_4}}}\mathop {B{{(O{C_2}{H_5})}_3}}\limits_{Triethyl\,\,\,borate}$

When ortho boric acid is burnt with ethyl alcohol in presence of Conc H₂SO₄ gives triethyl ortho borate.

When the vapours of triethyl borate ignited burn with a green edged flame.The green edged flame is due to the combustion of ethyl borate.

This test is used to detect the borates and boric acid in qualitative analysis.

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