Statement-I     If the interior angle of a $n$  sided regular polygon is $160°$ , then the number of sides are greater than the number of diagonals of the polygon.

Statement-II     In a regular hexagon, the exterior angle is half of the interior angle.

I)Interior angle of ‘n’ sided regular polygon $=\frac{(n-2)\times 180°}{n}$

$\frac{(n-2)\times 180°}{n}$ $=$  $160°$            ($n$  is number of sides of a polygon)

$(n-2)\times 180°$ $=$ $160°$ $\times$ $n$

$180n-360=160n$

$180n-160n=360$

$20n=360$

$n=18$

Number of sides of polygon =18.

Number of diagonals of 18 sided polygon $=$ $\frac{n(n-3)}{2}$

$=$ $\frac{18(18-3)}{2}$

$=$ $\frac{18\left(15\right)}{2}$

$=$ $9\times 15$

$=$ $135$

II)Interior angle of regular hexagon = 120°

Exterior angle of regular hexagon = 60°