Statement I : Melting point of n-pentane > Isopentane > Neopentane

Statement II : As branching increases London dispersion forces become stronger

Melting point is decided by the stability of the Lattice. Highly symmetrical hydrocarbons possess greater melting point.

London dispersion forces  $\mathrm{\alpha }$ Polarisability

                                            $\mathrm{\alpha }$ Size     

                                           $\mathrm{\alpha }$ Molar Mass

                                        $\mathrm{\alpha }$ Surface area

                                          $\propto \frac{1}{\text{ Branching }}$