Statement I: % of phosphorus =$\frac{31 \times {\mathrm{m}}_1 \times 100}{1877 \times \mathrm{m}}$

Statement II: In the above formula, molar mass of  ${{\text{(NH}}_{\text{4}})}_3{\text{\hspace{0.17em}PO}}_{\text{4}}12{\text{MoO}}_{\text{3}}=1877 \text{g}$, 31= atomic mass of phosphorous, m₁ = obtained mass of phosphorous and m = Total mass of the organic compound taken.

Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I.

Statement I is correct but Statement II is incorrect.

Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.

Both Statement I and Statement II are incorrect.