Statement-I      $\sin 2A=2\sin A$  is true for $A=0°$ .

$\mathbf{Statement}\mathbf{-}\mathbf{II}\mathbf{ } \frac{2\mathrm{tan\theta }}{1+{\tan }^2\mathrm{\theta }}=\sin 2\mathrm{\theta }$

Statement I is False, Statement II is True

Statement I is True, Statement II is True

Statement I is True, Statement II is False

Statement I is False, Statement II is False