Statement-I : The circle with the points of intersection of the line 3x+4y=12 with axes as extremities of a diameter is$x^2+y^2-4x-3y=0$
Statement-II : The circle passing through (0, 0) and making intercepts 8 and 6 on x, y axes, has its centre is (–4, 2).

Which of above statement is false ?

$$\begin{gathered} Statement1:Equation of circle with end points of diameter \\ are (4,0) and (0,3) is \\ (x-4)(x-0)+(y-0)(y-3)=0 \\ \Rightarrow x^2+y^2-4x-3y=0 \\ statement1 is true \\ Statement2: \\ circle pas\sin g through (0,0) then c=0 \\ Given that 2\sqrt{g^2-\mathrm{c}}=8 \\ \Rightarrow {\mathrm{g}}^2-\mathrm{c}=16 \\ \Rightarrow {\mathrm{g}}^2=16 \\ \Rightarrow \mathrm{g}=\pm 4 \\ and 2\sqrt{{\mathrm{f}}^2-\mathrm{c}}=6 \\ \Rightarrow \mathrm{f}=\pm 3 \\ centre of circle =(\pm 4,\pm 3) \\ So,statement2 is false. \end{gathered}$$

only II