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Q.

Statement I : When 0.1M weak diprotic acid H₂A dissociates with its dissociation constants K_a1= 10^-3and K_a2 =10^-8
and , then [A^–2] is almost equal to 10^–3M.
Statement II : Since $K_{a_{2}} < < K_{a_{1}}$ for 0.1 M H₂A, so [A^–2] is considerable w.r.t. [HA^–].

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a

Both statement - I and statement - II are False

b

Statement I is correct and Statement II is incorrect

c

Statement I and II are correct

d

Statement - I is incorrect and Statement II is correct

answer is D.

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Detailed Solution

$\underset{C_{0} - x}{H_{2} A} ⇌ \underset{x - y}{{HA}^{-}} + \underset{x + y}{H^{+}}; K_{a_{1}} = \frac{x \times x}{C_{0}}$

$\underset{x - y}{{HA}^{-}} ⇌ A_{y}^{- 2} + H_{y + x}^{+}; K_{a_{2}} = \frac{x \times y}{x}$

$K_{a_{1}} ≫ K_{a_{2}} \Rightarrow x ≫ y$

$\Rightarrow y = K_{a_{2}}$

$Also, C_{0} ≫ x$

$\Rightarrow [A^{- 2}] ≅ K_{a_{2}}$

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Statement I : When 0.1M weak diprotic acid H2A dissociates with its dissociation constants Ka1 = 10-3 and Ka2 =10-8 and , then [A–2] is almost equal to 10–3M.Statement II : Since Ka2<<Ka1 for 0.1 M H2A, so [A–2] is considerable w.r.t. [HA–].