Statement I : 1 mol of iron (Fe) reacts completely with 0.65 mol $O_{2}$ to give a mixture of only FeO and $F e_{2} O_{3}$ .
Statement II : Mole ratio of FeO & $F e_{2} O_{3}$ in the product mixture is 4 : 3.
In the light of the above statements, choose the most appropriate answer from the options given below:

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Both statement I and statement II are incorrect.

Both statement I and Statement II are correct.

Statement I is correct, Statement II is incorrect.

Statement I is incorrect, statement II is correct.

answer is A.

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Detailed Solution

$F e + 1 / 2 O_{2} \overset{}{\to} F \underset{a}{e} O$
$2 F e + 3 / 2 O_{2} \overset{}{\to} F {\underset{b}{e}}_{2} O_{3}$
Let a moles of FeO and b moles of $F e_{2} O_{3}$ is formed.
$\Rightarrow$ moles of Fe used = a+2b=1
$\Rightarrow$ moles of $O_{2} = \frac{a + 3 b}{2} = 0.65$
$\Rightarrow$ b = 0.3 and a = 0.4