Statement I : 1 mol of iron (Fe) reacts completely with 0.65 mol $O_{2}$ to give a mixture of only FeO and $F e_{2} O_{3}$ .
Statement II : Mole ratio of FeO & $F e_{2} O_{3}$ in the product mixture is 4 : 3.
In the light of the above statements, choose the most appropriate answer from the options given below:

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

Both statement I and statement II are incorrect.

Both statement I and Statement II are correct.

Statement I is correct, Statement II is incorrect.

Statement I is incorrect, statement II is correct.

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$F e + 1 / 2 O_{2} \overset{}{\to} F \underset{a}{e} O$
$2 F e + 3 / 2 O_{2} \overset{}{\to} F {\underset{b}{e}}_{2} O_{3}$
Let a moles of FeO and b moles of $F e_{2} O_{3}$ is formed.
$\Rightarrow$ moles of Fe used = a+2b=1
$\Rightarrow$ moles of $O_{2} = \frac{a + 3 b}{2} = 0.65$
$\Rightarrow$ b = 0.3 and a = 0.4