Statement – I: 1 mole of $H_{2} {SO}_{4}$ is neutralized by 2 moles of $NaOH$ . However, 1 equivalent of $H_{2} {SO}_{4}$ is neutralised by 1 equivalent of $NaOH .$
Statement –II: Equivalent mass of $H_{2} {SO}_{4}$ is half of its molecular mass. However, the equivalent mass of $NaOH$ is equal to its molecular mass.

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if statement I is correct, but statement II is incorrect.

if statement I is incorrect, but statement II is correct.

if both statement I and statement II are correct.

if both statement I and statement II are incorrect.

answer is A.

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Detailed Solution

$2 NaOH + H_{2} {SO}_{4} \to {Na}_{2} {SO}_{4} + 2 H_{2} O$

2 mol 1 mol

n-factor for $H_{2} {SO}_{4}$ = 2

according to law of equivalence

Number of equivalents of $H_{2} {SO}_{4}$ = Number of equivalents of $NaOH$

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