Statement-I: $3^{\log_{2}^{7}} - 7^{\log_{2}^{3}} = 0$
Statement-II: $x^{\log_{a}^{y}} = y^{\log_{a}^{x}}$ , where x > 0, y > 0 and a > 0, $a \neq 1$

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Statement –I is true, Statement –II is false.

Statement –I & II are true and statement-II is the correct explanation for statement-I

Statement –I is true, statement-II is true, statement-II is not correct explanation for statement-I

Statement –I is false, Statement –II is true.

answer is A.

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Detailed Solution

By law of loganthim $x^{\log_{a}^{y}} = y^{\log_{a}^{y}}$
$∴ 3^{\log_{2}^{7}} = 7^{\log_{2}^{3}} \Rightarrow 3^{\log_{2}^{7}} - 7^{\log_{2}^{3}} = 0$

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