Statement I : A solution of FeSO4 can be stored in a copper vessel.Statement II : E0 of Cu2+/Cu < E0 of Fe2+/Fe

Cu+2 →Cu and Fe →Fe+2 is spontaneous because Fe + CuSO4 → FeSO4 + Cu is a spontaneous reactionThus FeSO4 cannot be reduced by CuFeSO4 Can be stored in 'Cu' vesselStatement I is correct but statement II is false

Statement I : A solution of FeSO4 can be stored in a copper vessel.Statement II : E0 of Cu2+/Cu < E0 of Fe2+/Fe

Cu+2 →Cu and Fe →Fe+2 is spontaneous because Fe + CuSO4 → FeSO4 + Cu is a spontaneous reactionThus FeSO4 cannot be reduced by CuFeSO4 Can be stored in 'Cu' vesselStatement I is correct but statement II is false

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Statement I : A solution of FeSO₄ can be stored in a copper vessel.
Statement II : E⁰ of Cu²⁺/Cu < E⁰ of Fe²⁺/Fe

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Statement I and II are correct

Statement I is correct and II is incorrect

Statement I is incorrect and statement II is correct

Statement I & II are incorrect

answer is B.

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Detailed Solution

begin{gathered} E_{F{e^{ + 2}}/Fe}^0; = ; - 0.44V \ E_{C{u^{ + 2}}/Cu}^0; = ; + 0.34 \ end{gathered}

Cu⁺² →Cu and Fe →Fe⁺² is spontaneous because

large E_{C{u^{ + 2}}/Cu}^0; = ; + 0.34; > ;E_{F{e^{ + 2}}/Fe}^0; = ; - 0.44V

Fe + CuSO₄ → FeSO₄ + Cu is a spontaneous reaction
Thus FeSO₄ cannot be reduced by Cu
FeSO₄ Can be stored in 'Cu' vessel
Statement I is correct but statement II is false

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