Statement-I: Aniline is highly reactive towards electrophilic substitution reaction.
Statement-II: -NH₂ group of aniline shows -I, +M, effect.

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Both statements I and II are correct

Both statements I and II are incorrect.

Statement I is correct but statement II is incorrect

Statement I is incorrect but statement II is correct

answer is A.

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Detailed Solution

In aniline lone pair is less available for donation due to resonance. Aniline is less basic than ammonia.

Due to higher electronegativity of nitrogen as compared to carbon, -NH₂ gp shows “-I” effect.

Due to the donation of lonepair to benzene ring, -NH₂ gp shows “+M” effect .

+M effect >>> -I effect, it is highly activating group towards ESR.

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