Statement I : Aqueous solution of Na2CO3 is acidic in natureStatement II : Na+ ion undergoes hydrolysis to produce NaOH and H+ ions

Na2CO3 → 2Na+ + CO3-2 CO3-2 + 2H2O → H2CO3 + 2OH- 2Na+ + 2OH- → 2NaOH → Aqueous solution of Na2CO3 is basic in nature, since it undergoes anionic gydrolysis → The cations of strong base and the anions of strong acid in the salt can't undergoes hydrolysis In Na2CO3, the Na+ ion comes from strong base and hence it can't undergo hydrolysis. Where as CO3-2 ion comes from weak acid and hence it undergoes hydrolysis and produces H2CO3, OH- .Due to presence of OH- ion the solution possess alkali nature.

Statement I : Aqueous solution of Na2CO3 is acidic in natureStatement II : Na+ ion undergoes hydrolysis to produce NaOH and H+ ions

Na2CO3 → 2Na+ + CO3-2 CO3-2 + 2H2O → H2CO3 + 2OH- 2Na+ + 2OH- → 2NaOH → Aqueous solution of Na2CO3 is basic in nature, since it undergoes anionic gydrolysis → The cations of strong base and the anions of strong acid in the salt can't undergoes hydrolysis In Na2CO3, the Na+ ion comes from strong base and hence it can't undergo hydrolysis. Where as CO3-2 ion comes from weak acid and hence it undergoes hydrolysis and produces H2CO3, OH- .Due to presence of OH- ion the solution possess alkali nature.

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Statement I : Aqueous solution of Na₂CO₃ is acidic in nature
Statement II : Na⁺ ion undergoes hydrolysis to produce NaOH and H⁺ ions

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Both statement I and statement II are true, and statement II is correct explanation of statement I

Both statement I and statement II are true, and statement II is not the correct explanation of statement I

Statement I is true but statement II is false

Both statement I and II are false

answer is D.

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Detailed Solution

Na₂CO₃ → 2Na⁺ + CO₃^-2
CO₃^-2 + 2H₂O→ H₂CO₃ + 2OH^-
2Na⁺ + 2OH^- → 2NaOH
→ Aqueous solution of Na₂CO₃ is basic in nature, since it undergoes anionic gydrolysis
→ The cations of strong base and the anions of strong acid in the salt can't undergoes hydrolysis
$large therefore$ In Na₂CO₃, the Na⁺ ion comes from strong base and hence it can't undergo hydrolysis. Where as CO₃^-2 ion comes from weak acid and hence it undergoes hydrolysis and produces H₂CO₃, OH^- .Due to presence of OH^- ion the solution possess alkali nature.