Statement I : BeO and Al2O3 are amphoteric Statement II : Be and Al are made passive by HNO3

BeO and Al2O3 are amphoteric in nature.The oxides of both Be [BeO] and Al[Al2O3] are amphoteric and hence they dissolve in NaOH solution as well as in HClBeO + 2HCl → BeCl2 + H2O Al2O3 + 6HCl → 2AlCl3 + 3H2O Al2O3+2NaOH→2NaAlO2+H2OBe and Al become passive (resistant) on reaction with concentrated nitric acid due to formation of protective oxide layer on the surface of the Be and Al metals.

Statement I : BeO and Al2O3 are amphoteric Statement II : Be and Al are made passive by HNO3

BeO and Al2O3 are amphoteric in nature.The oxides of both Be [BeO] and Al[Al2O3] are amphoteric and hence they dissolve in NaOH solution as well as in HClBeO + 2HCl → BeCl2 + H2O Al2O3 + 6HCl → 2AlCl3 + 3H2O Al2O3+2NaOH→2NaAlO2+H2OBe and Al become passive (resistant) on reaction with concentrated nitric acid due to formation of protective oxide layer on the surface of the Be and Al metals.

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Statement I : BeO and Al₂O₃ are amphoteric
Statement II : Be and Al are made passive by HNO₃

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Statement I and II are correct

Statement I is incorrect and statement II is correct

Statement - I is correct and Statement - II is incorrect

Both statement - I and statement - II are incorrect

answer is A.

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Detailed Solution

BeO and Al₂O₃ are amphoteric in nature.

The oxides of both Be [BeO] and Al[Al₂O₃] are amphoteric and hence they dissolve in NaOH solution as well as in HCl
BeO + 2HCl → BeCl₂ + H₂O

large BeO; + ;2NaOH; to ;mathop {N{a_2}Be{O_2}}limits_{Sod.Berrylate} ; + ;{H_2}O

Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O

{Al}_{2} O_{3} + 2 NaOH \to 2 {NaAlO}_{2} + H_{2} O

Be and Al become passive (resistant) on reaction with concentrated nitric acid due to formation of protective oxide layer on the surface of the Be and Al metals.

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