Statement I: CuI₂ is not stable
Statement II:Cu⁺² gets reduced , I^- getsoxidised

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Statement I is correct Statement II is incorrect

Statement I and Statement II both are correct

Statement I is incorrect Statement II is correct

Statement I is incorrect Statement II is incorrect

answer is A.

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Detailed Solution

I^- ion is good reducing agent and it is stabilise the lowest oxidation state metals.so all Cu(II) halides are
known except the iodide. In this case, Cu²⁺oxidises I^– to I₂; 2Cu⁺² +4I^- $\to$ Cu₂I₂ +I₂

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