Statement-I: Fluoromethane $\left({\mathrm{CH}}_{3}F;\mu =1.85\mathrm{D}\right)$ has a smaller dipole moment than chlorometbane $\left({\mathrm{CH}}_3\mathrm{Cl};\mu =1.87\mathrm{D}\right)$

Statement-2: Fluorine has less electron affinity than that of chlorine.

The dipole moment of Fluoromethane is 1.85 which is less than that of chlorometbane (1.87 D).

Fluorine has a lower electron affinity than chlorine. This is because of the factors listed below: In contrast to chlorine, which has seven electrons in its 3p-subshell, fluorine has seven electrons in its 2p-subshell. Comparatively, 3p-subshell is larger than 2p-subshell.