Statement I : For the ellipse  $\frac{x^2}{5}+\frac{y^2}{3}=1$, the product of the perpendiculars drawn from the foci on any tangent is 3.
Statement II : For the ellipse  $\frac{x^2}{5}+\frac{y^2}{3}=1$, the foot of the perpendiculars drawn from the foci on any tangent lies on the circle  $x^2+y^2=5$  which is an auxiliary circle of the ellipse.