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Q.

Statement – I: If a>0 and b2-4ac<0 then the value of the integral dxax2+bx+c will be the type μtan1x+AB+C, where A,B,C, μ  are constants.

Statement – II: a>0 and b2-4ac<0, then ax2+bx+c can be written as the sum of two squares.

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a

Statement I is correct, Statement II is correct and Statement II is the correct explanation of Statement I

b

Statement I is correct, Statement II is correct, Statement II is not correct explanation of Statement I

c

Statement I is correct, Statement II is wrong

d

Statement I is wrong, Statement II is correct

answer is A.

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Detailed Solution

If a>0 and b2-4ac<0 then 1ax2+bx+cdx=1a(x2+2(b2a)x+b24a2-b24a2+ca)dx                                 =1a(x+b2a)2+4ac-b24adx                                    =1a(x+b2a)2+k2dx where k2=4ac-b24a>0                                    =1a1katan-1(x+b2aka)+C                                     =μtan-1(x+AB)+C where A,B,C,μ are constants

Assertion is correct, Reason is correct and Reason is the correct explanation of Assertion

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