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Q.

Statement I: If the circumference of the circle x2+y22x+8yq2=0 is bisected by the circle x2+y2+4x+22y+p2=0, then pq cannot exceed 25.
Statement II: Common chord of two circles must be equidistant from the centers of both circles.

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a

Both  Statement I and Staement II are correct and Statement II is correct explanation for Statement I

b

Statement I is True, Statement IIIIis True and Statement II is not correct explanation for Statement I

c

Statement I is True, Statement II is False

d

Statement I is False, Statement II is True

answer is C.

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Detailed Solution

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Equation of common chord is 6x+14y+p2+q2=0. it must pass through the center of first circle p2+q2=50 as p2+q22pqpq25

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