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Q.

Statement I: In a simple harmonic motion the kinetic and potential energies become equal when the displacement  is 12 times the amplitude. 
Statement II: In SHM kinetic energy is zero when potential energy is maximum.

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a

If both statement I and statement II are true and statement II is the correct explanation of statement I.
 

b

If both statement I and statement II are true but statement II is not the correct explanation of statement I.
 

c

If statement I is true but statement II is false 
 

d

If both statement I and statement II are false 
 

answer is B.

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Detailed Solution

From the relation, potential energy of SHM is given as PE = 122y2 and KE = 122(A2-y2)

where y is the displacement and A is the amplitufde 

By the condition KE = PE

122(A2-y2) = 122y2

mω2y2 = 12mω2A2

 y = A2

Also we know that total energy is E = KE + PE

Hence, if PE is maximum then KE will be zero.

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