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Q.

Statement-I: limx01cos2(3x)cos3(4x)sin3(4x)loge(2x+1)5 is equal to 18
Statement-II: Let k and m be positive real numbers such that the function f(x)={3x2+kx+1,   0<x<1mx2+k2,               x1 is differentiable for all x>0. Then f'(8)f'(18) is equal to 3098

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a

S-1 false, S-II is true

b

S-I false, S-II false

c

S-I true, S-II is false

d

S-I true, S-II true

answer is B.

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Detailed Solution

S-I: Divide numerator and denominator with x5
S-II: f is continuous at x=1
3+k2=m+k2 
f is differentiable at x=1
6+k2=2mk=742

f'(8)f'(18)=3098

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