Statement-I: The area bounded by $\mathrm{x} = 2 \mathrm{cos\theta }, \mathrm{y} = 3 \mathrm{sin\theta } \mathrm{is} 36 \mathrm{\pi }$ sq. units.
Statement-II : The area bounded by $\mathrm{x} = 2 \mathrm{cos\theta } , \mathrm{y} = 2 \mathrm{sin\theta } \mathrm{is} 4\mathrm{\pi }$ sq. units.
Which of the above statement is correct.

Statement-I: The area bounded by $\mathrm{x} = 2 \mathrm{cos\theta }, \mathrm{y} = 3 \mathrm{sin\theta } \mathrm{is} 36 \mathrm{\pi }$ sq. units

$\mathrm{x} = 2 \mathrm{cos\theta }, \mathrm{y} = 3 \mathrm{sin\theta } \Rightarrow {\left(\frac{x}{2}\right)}^2+{\left(\frac{y}{3}\right)}^2=1$

$Area enclosed by the ellipse \frac{x^2}{4}+\frac{y^2}{9}=1 is \mathrm{\pi ab}=\mathrm{\pi }\left(2\right)\left(3\right)=6\mathrm{\pi }$

Statement-II : The area bounded by $\mathrm{x} = 2 \mathrm{cos\theta } , \mathrm{y} = 2 \mathrm{sin\theta } \mathrm{is} 4\mathrm{\pi }$ sq. units

$$\begin{gathered} \mathrm{x} = 2 \mathrm{cos\theta } , \mathrm{y} = 2 \mathrm{sin\theta } \Rightarrow x^2+y^2=4\left({\cos }^2\theta +{\sin }^2\theta \right) \\ (i.e) x^2+y^2=4 \end{gathered}$$

Area enclosed by the circle $x^2+y^2=4 is {\mathrm{\pi r}}^2=4\mathrm{\pi }$