Statement I :The energy of 4s – orbital is lower than 3d-orbital till Ca(Z = 20) but after Sc (Z = 21), the order of energy is reversed.
Statement II: (n + l) value of 3d-orbital is greater than that of 4s-orbital.
In the light of the above statements, choose the most appropriate answer from the options given below:

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

Both statement I and statement II are incorrect.

Both statement I and Statement II are correct.

Statement I is correct, Statement II is incorrect.

Statement I is incorrect, statement II is correct.

answer is A.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

(n + l) value of 3d – orbital is (3 + 2) = 5 which that of 4s – orbital is (4 + 0) = 4.

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test