Q.

Statement  I :The energy of 4s – orbital is lower than 3d-orbital till Ca(Z = 20) but after Sc (Z = 21), the order of energy is reversed.
Statement  II:  (n + l) value of 3d-orbital is greater than that of 4s-orbital.
In the light of the above statements, choose the most appropriate answer from the options given below:

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a

Both statement  I and statement  II  are incorrect.

b

Both statement  I and Statement  II are correct.

c

Statement  I is correct, Statement  II is incorrect.  

d

Statement  I is incorrect, statement  II is correct.

answer is A.

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Detailed Solution

(n + l) value of 3d – orbital is (3 + 2) = 5  which that of 4s – orbital is (4 + 0) = 4.

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