Statement – I : The number of all ten digited numbers that can be formed with all the distinct digits and which are divisible by 4 is $20\times 8!$ 
 Statement – II : The number of positive integers that can be formed by using the digits 0,1,2,3,4,5 without repetition is 1630.
 

We have 0,1,2,3,4,5,6,7,8,9,
There are 16 last two digit numbers that are divisible by 4 without using zero. So, total number of such 10 Digit numbers  $=7\times 7!\times 16$
 Again, there are 6 last two digits numbers that are divisible by 4 with using zero. So, total number of such 10-digit Numbers $=8!\times 6$ required no. of ways   $=7\times 8!\times 2+8!\times 6 =7\times 8!\times 2+8!\times 6=20\times 8!$
 Similarly, six digit numbers =  $5\times 5\times 4\times 3\times 2\times 1=600$
           Five digit numbers =  $5\times 5\times 4\times 3\times 2=600$
         Four digit numbers =  $5\times 5\times 4\times 3=300$
      Three digit numbers  $=5\times 5\times 4=100$
      Two digit numbers  $=5\times 5=25$
          One digit numbers = 5
              Total =1630