Statement-I: The orbital angular momentum of 2s-electron is equal to that of 3s-electron.
Statement-II: The orbital angular momentum is given by the relation $\frac{h}{2 π} \sqrt{l (l + 1)}$ and the value of it is same for 2s-electron and 3s-electron.

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Both S-I and S-II are correct.

S-I in incorrect, S-II is correct.

S-I is correct, S-II is incorrect.

Both S-I and S-II are incorrect.

answer is A.

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Detailed Solution

The formula for orbital angular momentum $= \sqrt{l (l + 1)} \frac{h}{2 π}$
Since all s-orbitals have same l value i.e., 0, therefore, all orbitals have 0 angular momentum of their electrons.

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